Die lustige Zwölf

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At the beginning of the game, each player places 10 coins on space 6. The players roll two dice and places 5 coins on the space with the rolled number if the space is empty. If not, he wins the 5 coins from this space. On the roll of a 6, five coins are payed every time. If a 12 is rolled, the player wins the game and all coins on the board.

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